Question
A bar of uniform cross section and weighing 100 N is held horizontally using two massless and inextensible strings S1 and S2 as shown in the figure.
The tensions in the strings are
Options :
T1 = 100 N and T2 = 0 N
T1 = 0 N and T2 = 100 N
T1 = 75 N and T2 = 25 N
T1 = 25 N and T2 = 75 N
Answer :
T1 = 0 N and T2 = 100 N
Solution :
ΣMS1 = 0
T2 × L/2 = W × L/2
T2 = W = 100 N
ΣFy = 0 ⇒ T1 + T2 = W
⇒ T1 = 0
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