Question
A block moves down a smooth inclined plane of inclination θ. Its velocity on reaching the bottom is v. If it slides down a rough inclined plane of same inclination its velocity on reaching the bottom is v/n, where n is a number greater than 0. The coefficient of friction is given by μ is given by
Options :
μ = tan θ(1-1/n²)
μ = cot θ(1-1/n²)
μ = tan θ(1-1/n²)⁰.⁵
μ = cot θ(1-1/n²)⁰.⁵
Answer :
μ = cot θ(1-1/n²)
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