Question

A cast product of a particular material has dimensions 75 mm x 125 mm x 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinov’s rule having the index, n = 2. If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be _______________ minutes (round off to two decimal places).

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Answer :

Correct answer is : 2.82

Steel rectangular plate with dimensions = 75 mm × 125 mm × 20 mm, t = 2 minutes

Modulus of steel plate  = 75 × 125 × 20 2 [ ( 75 × 125 ) + ( 20 × 125 ) + ( 75 × 20 ) ] = 7 m m

Cylinder H = 50 mm, D = 50 mm.

Modulus for cylinder shape  = D 6 = 50 6 = 8.33 m m

Time ∝ (Modulus)2

T i m e o f c y l i n d e r T i m e o f p l a t e = ( M o d u l e o f c y l i n d e r M o d u l e o f p l a t e ) 2

t 2 = ( 8.33 7 ) 2

∴ t = 2.83 minutes

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