Question

A CNC worktable is driven in a linear direction by a lead screw connected directly to a stepper motor. The pitch of the lead screw is 5 mm. The stepper motor completes one full revolution upon receiving 600 pulses. If the work table speed is 5 m/minute and there is no missed pulse, then the pulse rate being received by the stepper motor is

Options :

  1. 20 kHz

  2. 10 kHz

  3. 3 kHz

  4. 15 kHz

Show Answer

Answer :

10 kHz

Solution :

Table speed = 5 m/minute = 5000/60 mm/sec

pitch = 5 mm

pulse per revolution = 600

So, in 1 revolution distance travel = 5 mm

So in 600 pulses distance travel = 5 mm

i.e. BLU =  5 600 mm/pulses

Frequency f =  T a b l e   s p e e d B L U 5000   ×   600 60   ×   5

f = 10000 Hz = 10 kHz

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