Answer :

Correct answer is : 0.93

There are 5 men and 3 women. Company is hiring to fill four managerial vacancies.

Probability that at least one woman will be selected = 1 - Probability that no woman is selected

Probability that no woman is selected = $\frac{{}^5{C}_4{\times }^3{C}_0}{{}^8{C}_4}=\frac{5\times 1}{70}=\frac{5}{70}$

Probability that at least one woman will be selected = 1 - Probability that no woman is selected = 1 - (5/70) = 65/70 = 0.93