Answer :

Correct answer is : 0.25

Law of conservation of angular momentum: the angular momentum of a system remains conserved as long as there is no net external torque acting on the system.

angular momentum, $\overrightarrow{l}=I\times \omega =\overrightarrow{r}\times \overrightarrow{p}$ = m × V × r

where, m = mass, V = velocity, r = radius

p = linear momentum = m × V

I = moment of inertia = mr²

ω = angular velocity = $\frac{V}{r}$

A is the center of mass(CM), B is the point of contact

Given:

mass m = 1 kg, r = 0.15 m, 𝜔 = 5 rad/s

Moment of inertia for the disc I = mr²/2 = 0.01125 mm​

By the law of conservation of angular momentum:

Initial angular momentum = Final angular momentum

$\therefore I_o{\omega }_o=I_f{\omega }_f+mVr$ $\Rightarrow$$\frac{m{r}^2}{2}\times {\omega }_o=\frac{3m{r}^2}{2}\times {\omega }_f$

${\omega }_f=\frac{{\omega }_o}{3}=\frac{5}{5}=1.667rad/sec$

$V={\omega }_f\times r=1.667\times 0.15=0.25\frac{m}{sec}$