Test Academy | A particle of mass ‘m’ is projected with a velocity v=kVe (k < 1) from the surface of the earth. (Ve=escape velocity) The maximum height above the surface reached by the particle is : R( k 1 − k ) 2 , R ( k 1 + k ) 2 , R 2 k 1 + k , R k 2 1 − k 2

Question

A particle of mass ‘m’ is projected with a velocity v=kVe (k < 1) from the surface of the earth. (Ve=escape velocity) The maximum height above the surface reached by the particle is :

Options :

$R(\frac{k}{1 - k})^{2}$
R $(\frac{k}{1 + k})^{2}$
$\frac{R^{2} k}{1 + k}$
$\frac{R k^{2}}{1 - k^{2}}$

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