Test Academy | A particle performing simple harmonic motion according to y = A sinωt. Then its kinetic energy (K.E.), potential energy (P.E.) and speed (V) at position y = A/2 are K . E = k A 2 8 P . E = 3 k A 2 8 V = A 3 k m , K . E = 3 k A 2 8 P . E = k A 2 8 V = A 2 3 k m , K . E = 3 k A 2 8 P . E = k A 2 4 V = A 3 k m , K . E = k A 2 4 P . E = 3 k A 2 8 V = A 4 3 k m

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A particle performing simple harmonic motion according to y = A sinωt. Then its kinetic energy (K.E.), potential energy (P.E.) and speed (V) at position y = A/2 are

Options :

$K . E = \frac{k A^{2}}{8}$ $P . E = \frac{3 k A^{2}}{8}$ $V = \frac{A}{3} \sqrt{\frac{k}{m}}$
$K . E = \frac{3 k A^{2}}{8}$ $P . E = \frac{k A^{2}}{8}$ $V = \frac{A}{2} \sqrt{\frac{3 k}{m}}$
$K . E = \frac{3 k A^{2}}{8}$ $P . E = \frac{k A^{2}}{4}$ $V = A \sqrt{\frac{3 k}{m}}$
$K . E = \frac{k A^{2}}{4}$ $P . E = \frac{3 k A^{2}}{8}$ $V = \frac{A}{4} \sqrt{\frac{3 k}{m}}$

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