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Question

A particle performing simple harmonic motion in such that it’s amplitude is 4 m and speed of particle at mean position is 10 m/s. Find the distance of particle from mean position where velocity became 5 m/s.

Options :

  1. √ 3 m

  2. 2√ 3 m

  3. √ 3/2 m

  4. 1/√ 2 m

Show Answer

Answer :

2√ 3 m

Solution :

v = ω A 2 − x 2

In 1st case : at x = 0, v = 10 m/s

then 10 = ω ( 4 ) 2 − 0 2

ω = 10 4 = 5 2 r a d / s

In 2nd case :

5 = 5 2 ( 4 ) 2 − x 2

x = 2 3 m

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