Question
A steel part with surface area of 125 cm² is to be chrome coaled through an electroplating process using chromium acid sulphate as an electrolyte. An increasing current is applied to the part according to the following current time relation :
I = 12 + 0.2t
where, I = current (A) and t = time (minutes). The part is submerged in the plating solution for a duration of 20 minutes for plating purpose. Assuming the cathode efficiency of chromium to be 15% and the plating constant of chromium acid sulphate to be 2.50 × 10–2 mm³/A·s, the resulting coating thickness on the part surface is _________ μm (round off to one decimal place).
Answer :
Correct answer is : 5.0
I = 12 + 0.2t
After time, 't', Next infinitely small time 'dt' let heat deposited 'dQ'
∴ dQ = 2.50 × 10-2 (mm3/A.s) × 12 + 0.2t × dt
As we have to convert this 's' to 'min'
∴ dQ = 2.50 × 10-2 (mm3/A × min) × 12 + 0.2t × dt
Considering cathode efficiency of 15%
dQ = 2.50 × 10-2 × 60 × (12 + 0.2t)dt × 0.15 mm3
∴ In 20 min, 2.50 × 10-2 × 60 × (12 + 0.2t)dt × 0.15
= 0.225[12 × 20 + 0.1 × 202] mm3
= 63 mm3
As area os 125 cm2
Plating thickness,
Copyright © 2025 Test Academy All Rights Reserved