Question
A through hole is drilled in an aluminum alloy plate of 15 mm thickness with a drill bit of diameter 10 mm, at a feed of 0.25 mm/rev and a spindle speed of 1200 rpm. If the specific energy required for cutting this material is 0.7 N-m/mm³, the power required for drilling is W (round off to two decimal places).
Answer :
274.89 W
Power required = Specific energy consumption × MRR
Specific energy consumption = 0.7 Nm/mm3 = 0.7 J/mm3
MRR = (πd²/4) • fN = (π10²/4) • 0.25•1200 mm³/min
= 23561.94 mm³/min = 392.7 mm³/s
Power , P = 0.7 • 392.7 = 274.89 J/s = 274.89 W
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