Question

A two metre long rod is suspended with the help of two wires of equal length. One wire is of steel and its cross-sectional area is 0.1 cm² and another wire is of brass and its cross-sectional area is 0.2 cm². If a load W is suspended from the rod and stress produced in both the wires is same then the ratio of tensions in them will be

Options :

  1. Will depend on the position of W

  2. T₁ / T₂ = 2

  3. T₁ / T₂ = 1

  4. T₁ / T₂ = 0.5

Show Answer

Answer :

T₁ / T₂ = 0.5

Report
More Similar Tests

Related Tests