Question
A vessel of area of cross-section A has liquid to a height H. There is a hole at the bottom of vessel having area of cross-section a. The time taken to decrease the level from H₁ to H₂ will be
Options :
(A/a){(√2/g)}[√H₁-√H₂]
√(2gh)
√{2gh(H₁-H₂)}
(A/a){√(g/2)}[√H₁-√H₂]
Answer :
(A/a){(√2/g)}[√H₁-√H₂]
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