Question
An aluminum rod has a breaking strain of 0.2%. The minimum cross sectional area of the rod, in m² , in order to support a load of 10⁴ N is (Y = 7 x 10⁹ N / m²)
Options :
1.4 x 10⁻⁴
7.1 x 10⁻⁴
1.4 x 10⁻³
7.1 x 10⁻⁵
Answer :
7.1 x 10⁻⁴
Copyright © 2025 Test Academy All Rights Reserved