Question

Consider the circuit shown. Galvanometer resistance is 10 Ω and current through galvanometer is 3 mA. Find the resistance of shunt.

Options :

  1. 10–3 Ω

  2. 7.5 × 10–3 Ω

  3. 6.75 × 10–3 Ω

  4. 3.75 × 10–3 Ω

Show Answer

Answer :

3.75 × 10–3 Ω

Solution :

Since G and S are in parallel

VG = VS

3 mA × 10 = 8 A × RS

RS = 3.75 m Ω

Report
More Similar Tests

Related Tests

  • JEE
  • intermediate
  • 3 hours
  • physics, chemistry, mathematics

Prepare for success with our JEE Advanced Paper 2 Mock Test, designed to simulate the actual exam experience. This test covers Physics, Chemistry, and Mathematics with a balanced mix of conceptual and application-based questions. Sharpen your problem-solving skills and time management with carefully curated questions that align with the latest JEE syllabus. Boost your confidence and gauge your readiness for the big day!

Sophia Jaymes
By Physics Philosopher
  • JEE
  • intermediate
  • 3 hours
  • physics, chemistry, mathematics

Prepare for the JEE Advanced with our comprehensive Paper 1 Mock Test, designed to simulate the actual exam experience. Sharpen your problem-solving skills with a challenging mix of Physics, Chemistry, and Mathematics questions tailored to test your knowledge and speed.

Sophia Jaymes
By Physics Philosopher