Question
Currents through ammeters A2 and A3 in the figure are 1∠10° and 1∠70°, respectively. The reading of the ammeter A1 (rounded off to 3 decimal places) is _____ A.
Answer :
Ans. 1.732
By applying KCL at the node,
I1 = I2 + I3
I1 = 1∠10° + 1∠70°
= (cos 10 + j sin 10) + (cos 70 + j sin 70)
= (cos 10 + cos 70) + j(sin 10 + sin 70)
= 1.3268 + j1.1133 A
⇒ I1 = 1.732∠ 40° A
Copyright © 2025 Test Academy All Rights Reserved