Question
Find the approximate value of f(4.04), where f(x)=7x³+6x²-4x+3
Options :
346.2
544.345
546.2
532.2
Answer :
546.2
Prepare for success with our JEE Advanced Paper 2 Mock Test, designed to simulate the actual exam experience. This test covers Physics, Chemistry, and Mathematics with a balanced mix of conceptual and application-based questions. Sharpen your problem-solving skills and time management with carefully curated questions that align with the latest JEE syllabus. Boost your confidence and gauge your readiness for the big day!
Copyright © 2025 Test Academy All Rights Reserved