Test Academy | For a simple compressible system v, s, p and T are specific volume, specific entropy, pressure and temperature, respectively. As per Maxwell’s relations, (∂v /∂s) p is equal to (∂T/∂p)s, (∂p/∂v)T, (∂s/∂T)p, -(∂T/∂v)p

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For a simple compressible system v, s, p and T are specific volume, specific entropy, pressure and temperature, respectively. As per Maxwell’s relations, (∂v /∂s)_p is equal to

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