Answer :

Solution :

$[Co(N{H}_3{)}_6{]}^{3+}$

$[Co(N{H}_3{)}_6{]}^{3+}-\; <!--\; -\; -->d^{2}s{p}^3$hybridization

$Br{F}_5-\; <!--\; -\; -->s{p}^3{d}^2$ hybridization

$[PtC{l}_4{]}^{-\; <!--\; -\; -->2}-\; <!--\; -\; -->ds{p}^2$ hybridization

$S{F}_6-\; <!--\; -\; -->s{p}^3{d}^2$ hybridization