Answer :

Solution :

⊕ ÷ ⊙ = 2, Δ × ⊗ = 10, ⊙ + Δ = 5; Δ × ⊗ = 10

∵ $\frac{\oplus }{\odot }=2$ , $\frac{\oplus }{\Delta }=3$

∴ $\frac{\odot }{\Delta }=\frac{3}{2}$

$\odot =\frac{3\Delta }{2}$

now, ⊙ + Δ = 5

$\frac{3\Delta }{2}+\Delta =5$

5Δ = 10

∴ Δ = 2

∵ ⊙ + 2 = 5

∴ ⊙ = 3

Now, Δ × ⊗ = 10

2 × ⊗ = 10

∴ ⊗ = 5

Now, $\frac{\oplus }{\odot }=2$

$\frac{\oplus }{3}=2$

∴ ⊕ = 6

Hence (⊗ - ⊕)² = (5 - 6)² = 1