Question
If f(x) = 6x – x2, x ∈ [0, 2] and g ( x ) = { min f ( t ) , 0 ≤ t ≤ x , x ∈ [ 0 , 1 ] 3 + x , x ∈ [ 1 , 2 ] Then number of points where g(x) is not differentiable is
Options :
1
0
2
3
Answer :
Solution :
g ( x ) = { min f ( t ) , 0 ≤ t ≤ x , x ∈ [ 0 , 1 ] 3 + x , x ∈ [ 1 , 2 ]
Number of points of non-differentiability is 1.
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