Test Academy | If f(x) = 6x – x2, x ∈ [0, 2] and g ( x ) = { min f ( t ) , 0 ≤ t ≤ x , x ∈ [ 0 , 1 ] 3 + x , x ∈ [ 1 , 2 ] Then number of points where g(x) is not differentiable is 1, 0, 2, 3

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If f(x) = 6x – x2, x ∈ [0, 2] and $g (x) = {\begin{cases} min f (t), 0 \leq t \leq x, x \in [0, 1] \\ 3 + x, x \in [1, 2] \end{cases}$ Then number of points where g(x) is not differentiable is

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