Test Academy | If H : x 2 16 − y 2 9 = 1 and E : x 2 a 2 + y 2 b 2 = 1 ( a > b ) . Ellipse passes through the foci of the hyperbola and e 1 . e 2 = 1 (where e 1 , e 2 are the eccentricities of hyperbola and ellipse, respectively). The length of the chord of ellipse passing through (0, 2) is equal to 5√10/3, 10√5/3, 2√5, 2√10

Question

If $H : \frac{x^{2}}{16} - \frac{y^{2}}{9} = 1$ and $E : \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 (a > b) .$ Ellipse passes through the foci of the hyperbola and e₁. e₂ = 1 (where e₁, e₂ are the eccentricities of hyperbola and ellipse, respectively). The length of the chord of ellipse passing through (0, 2) is equal to

Options :

5√10/3
10√5/3
2√5
2√10

Show Answer

Report

More Similar Tests

Related Tests

JEE
intermediate
3 hours
physics, chemistry, mathematics

JEE Advanced Paper 2 Mock Test

Prepare for success with our JEE Advanced Paper 2 Mock Test, designed to simulate the actual exam experience. This test covers Physics, Chemistry, and Mathematics with a balanced mix of conceptual and application-based questions. Sharpen your problem-solving skills and time management with carefully curated questions that align with the latest JEE syllabus. Boost your confidence and gauge your readiness for the big day!

By Physics Philosopher

JEE
intermediate
3 hours
physics, chemistry, mathematics

JEE Advanced Paper 1 Mock Test

Prepare for the JEE Advanced with our comprehensive Paper 1 Mock Test, designed to simulate the actual exam experience. Sharpen your problem-solving skills with a challenging mix of Physics, Chemistry, and Mathematics questions tailored to test your knowledge and speed.

By Physics Philosopher