Test Academy | If n-1 C r = (k 2 - 8) n C r+1 then k ∈ [ − 3 , − 2 2 ) ∪ ( 2 2 , 3 ] , k ∈ [ − 4 , − 2 3 ) ∪ ( 2 3 , 4 ] , k ∈ [ − 2 3 , 4 ] , k ∈ [ 3 , 2 3 ]

Question

If ^n-1C_r = (k² - 8)ⁿC_r+1 then

Options :

$k \in [- 3, - 2 \sqrt{2}) \cup (2 \sqrt{2}, 3]$
$k \in [- 4, - 2 \sqrt{3}) \cup (2 \sqrt{3}, 4]$
$k \in [- 2 \sqrt{3}, 4]$
$k \in [3, 2 \sqrt{3}]$

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