Question

In a vapor compression refrigeration cycle, the refrigerant enters the compressor in saturated vapor state at evaporator pressure, with specific enthalpy equal to 250 kJ/kg. The exit of the compressor is superheated at condenser pressure with specific enthalpy equal to 300 kJ/kg. At the condenser exit, the refrigerant is throttled to the evaporator pressure. The coefficient of performance (COP) of the cycle is 3. If the specific enthalpy of the saturated liquid at evaporator pressure is 50 kJ/kg, then the dryness fraction of the refrigerant at entry to evaporator is _________.

Options :

  1. 0.2

  2. 0.25

  3. 0.3

  4. 0.35

Show Answer

Answer :

0.25

Solution :

hf = 50 kJ/kg

COP = 3, h1 = 250 kJ/kg , h2 = 300 kJ/kg

COP =  h 1     h 4 h 2     h 1

3 =  250     h 4 300     250 ⇒ h4 = 100 kJ/kg

h4 = hf + x hfg

100 = 50 + x (h1 - hf )

50 = x (250 - 50)

x = 50/200 ⇒ x = 0.25

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