Test Academy | Let [ε₀] denotes the dimensional formula of the permittivity of the vacuum and [μ₀] that of the permeability of the vacuum. If M = mass, L= length, T= time and I= electric current, then [ε₀] = M⁻¹L⁻³T²I, [ε₀] = M⁻¹L⁻³T⁴I², [μ₀] = MLT⁻²I⁻², [μ₀] = ML²T⁻¹I

Question

Let [ε₀] denotes the dimensional formula of the permittivity of the vacuum and [μ₀] that of the permeability of the vacuum. If M = mass, L= length, T= time and I= electric current, then

Options :

[ε₀] = M⁻¹L⁻³T²I
[ε₀] = M⁻¹L⁻³T⁴I²
[μ₀] = MLT⁻²I⁻²
[μ₀] = ML²T⁻¹I

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