Question

Periodic time of a satellite revolving above Earth’s surface at a height equal to R, where R the radius of Earth, is [g is acceleration due to gravity at Earth’s surface]

Options :

  1. 2π √(2R/g)

  2. 4 √2 π √(R/g)

  3. 2π √(R/g)

  4. 8π √(R/g)

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Answer :

4 √2 π √(R/g)

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