Question
S1 = 3, 9, 15, ... 25 terms S2 = 3, 8, 13, ... 37 terms Number of common terms in S1, S2 is equal to
Options :
3
4
5
6
Answer :
5
Solution :
S1 = 3, 9, 15 .... 147
d1 = 6, a1 = 3
S2 = 3, 8, 13, ... 183
d2 = 5, a2 = 3
LCM (d1, d2) = 30
∴ 3, 33, ... 123
∴ 123 = 3 + (n – 1)30
⇒ n = 5
∴ Number of common terms = 5
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