Question
Solution of ∇2𝑇 = 0 in a square domain (0 < x < 1 and 0 < y < 1) with boundary conditions: T(x, 0) = x; T(0, y) = y; T(x, 1) = 1 + x; T(1,y) = 1 + y is
Options :
T(x, y) = x – xy + y
T(x, y) = x + y
T(x, y) = –x + y
T(x, y) = x + xy + y
Answer :
T(x, y) = x + y
Solution :
T(x, 0) = x ⇒ option (c) is not correct.
T(0, y) = y ⇒ all options satisfied.
T(x, 1) = 1 + x ⇒ only option (b) is satisfied.
T(1, y) = 1 + y ⇒ only option (b) is satisfied.
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