Question

The diagram shows combination of polaroids.Unpolarised light of intensity I0 incident perpendicular to the axis of polaroid P1, then angle θ for which maximum intensity passes through polaroid P3

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Answer :

Correct answer is : 45

I 3 = I 0 2 × 4 sin 2 θ cos 2 θ 4

= I 0 8 ( sin 2 θ ) 2

For I3 → max

sin2θ = 1

2θ = 90°

θ = 45°

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