Question
The Fourier series expansion of x3in the interval −1 ≤ x < 1 with periodic continuation has
Options :
only sine terms
only cosine terms
both sine and cosine terms
only sine terms and a non-zero constant
Answer :
only sine terms
Solution :
Function f ( x) = x3 ; -1 ≤ x < 1 The above function f (x) is odd. We know that, odd function contains only odd terms,
a0 and an will be zero.
Therefore, the given function f (x) contains only sine term.
Hence, the correct option is (A).
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