Question
The frequency of vibration f of a mass m suspended from a spring of spring constant k is given by a relation f = amˣkʸ, where a is a dimensionless constant. The values of x and y are
Options :
x = 1/2 , y =1/2
x = -1/2 , y = -1/2
x = 1/2 , y = -1/2
x = -1/2 , y =1/2
Answer :
x = -1/2 , y =1/2
Prepare for success with our JEE Advanced Paper 2 Mock Test, designed to simulate the actual exam experience. This test covers Physics, Chemistry, and Mathematics with a balanced mix of conceptual and application-based questions. Sharpen your problem-solving skills and time management with carefully curated questions that align with the latest JEE syllabus. Boost your confidence and gauge your readiness for the big day!
Copyright © 2025 Test Academy All Rights Reserved