Question
The integral ∫ ( x 8 − x 2 ) d x ( x 12 + 3 x 6 + 1 ) tan − 1 ( x 3 + 1 x 3 ) is equal to
Options :
1 3 ln | ( tan − 1 ( x 3 + 1 x 3 ) ) | + C
ln | ( tan − 1 ( x 3 + 1 x 3 ) ) | + C
1 6 ln | ( tan − 1 ( x 3 + 1 x 3 ) ) | + C
1 9 ln | ( tan − 1 ( x 3 + 1 x 3 ) ) | + C
Answer :
Solution :
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