Question
The maximum clock frequency in MHz of a 4-stage ripple counter, utilizing flip-flops, with each flip-flop having a propagation delay of 20 ns, is _______. (round off to one decimal place).
Answer :
12.5 (Range : 12.3 to 12.7)
Given :
(i) 4-stage ripple counter
(ii) Number of bits n = 4
(iii) Propagation delay of each flip-flop tpd=20 nsec
(iv) Maximum clock frequency of n-state ripple counter,
fCLK=1/ntpd= 4 × 20 × 10-9= 12.5 MHz
Hence, the correct answer is 12.5.
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