Question
The maximum reduction in cross-sectional area per pass ( R ) of a cold wire drawing process is
R= 1-e-(n+1)
where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is
Options :
0.865
0.865
0.777
0.632
Answer :
0.632
Solution :
The value of ‘n’ for perfectly plastic material [n = 0] ‘n’ is a strain hardening coefficient.
Given, R = 1 – e-(n + 1)
Also for perfectly plastic material, n = 0
⇒ R = 1 – e-1
= 1-1/e = 0.632
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