Question

The maximum reduction in cross-sectional area per pass ( R ) of a cold wire drawing process is

                                                                         R= 1-e-(n+1)

where n represents the strain hardening coefficient. For the case of a perfectly plastic material, R is

Options :

  1. 0.865

  2. 0.865

  3. 0.777

  4. 0.632

Show Answer

Answer :

0.632

Solution :

The value of ‘n’ for perfectly plastic material [n = 0] ‘n’ is a strain hardening coefficient.


Given, R = 1 – e-(n + 1)

Also for perfectly plastic material, n = 0

⇒ R = 1 – e-1

         = 1-1/e = 0.632

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