Question

The peak wavelength of radiation emitted by a black body at a temperature of 2000 K is 1.45 µm. If the peak wavelength of emitted radiation changes to 2.90 µm, then the temperature (in K) of the black body is

Options :

  1. 500

  2. 1000

  3. 4000

  4. 8000

Show Answer

Answer :

1000

Solution :

From Wein's displacement law

λmaxT = 2898µm -k(constant)

Thus, λpeakT = λ'peakT'


Black body λ'peak = 1.45 μm at 2000 K.

Now, λ'peak =8.90µm

1.45*2000 = 2.90*T'

T'= 1000K

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