Question
The peak wavelength of radiation emitted by a black body at a temperature of 2000 K is 1.45 µm. If the peak wavelength of emitted radiation changes to 2.90 µm, then the temperature (in K) of the black body is
Options :
500
1000
4000
8000
Answer :
1000
Solution :
From Wein's displacement law
λmaxT = 2898µm -k(constant)
Thus, λpeakT = λ'peakT'
Black body λ'peak = 1.45 μm at 2000 K.
Now, λ'peak =8.90µm
1.45*2000 = 2.90*T'
T'= 1000K
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