Question
The product of three integers X, Y and Z is 192. Z is equal to 4 and P is equal to the average of X and Y. What is the minimum possible value of P?
Options :
7
6
8
9.5
Answer :
7
Solution :
XYZ = 192 and Z = 4
So, XY = 48
P = (X + Y) /2
For finding the minimum possible of P, X + Y should be minimum
Now, the possible values of X and Y are as follows
| X | Y |
| 48 | 1 |
| 24 | 2 |
| 16 | 3 |
| 12 | 4 |
| 8 | 6 |
So, from this we can clearly see that X + Y will be minimum only when X = 8 and Y = 6 or viceversa
So minimum value of P = (8+6)/2 = 7
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