Question
The total kinetic energy of 1 mole of oxygen at 27°C is : [Take R = (25/3) J/mol-K]
Options :
6250 J
3125 J
12500 J
625 J
Answer :
6250 J
Solution :
(f = 5 for diatomic gas)
K = 5/2 μRT = 5/2 * 1 * 25/3 * 300
= 250 × 25
= 6250 J
Copyright © 2025 Test Academy All Rights Reserved