Test Academy | Two particles of equal mass go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is v = (1/2R)(√1/Gm), v = √(Gm/2R), v = (1/2)√(Gm/R), v = √(4Gm/R)

Question

Two particles of equal mass go round a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

Options :

v = (1/2R)(√1/Gm)
v = √(Gm/2R)
v = (1/2)√(Gm/R)
v = √(4Gm/R)

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