Question
Under orthogonal cutting condition, a turning operation is carried out on a metallic workpiece at a cutting speed of 4 m/s. The orthogonal rake angle of the cutting tool is 5°. The uncut chip thickness and width of cut are 0.2 mm and 3 mm, respectively. In this turning operation, the resulting friction angle and shear angle are 45º and 25°, respectively. If the dynamic yield shear strength of the workpiece material under this cutting condition is 1000 MPa, then the cutting force is ______________ N (round off to one decimal place).
Answer :
Correct answer is 2573.40
shear strength, τs = 1000 MPa, cutting speed, V = 4 m/s
rake angle α = 5° , uncut chip thickness, t = 0.2 mm
width of cut w = 3 mm, friction angle β = 45°
shear angle ϕ = 25°
, Fs =
cutting force Fc =
Fc = 1000 x
Fc = 2573.40 N
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