Answer :

Solution :

f(x) = ${\int }_4^{5.2}$ln x dx, h = 0.3

b = 5.2, a = 4

$n=\frac{b-a}{h}=\frac{5.2-4}{0.3}$ = 4

x 4 4.3 4.6 4.9 5.2 y ln 4 ln 4.3 ln 4.6 ln 4.9 ln 5.2 y0 y1 y2 y3 y4

$I=\frac{h}{3}\left[y_0+y_4+4\left(y_1+y_3\right)+2\left(y_2\right)\right]$

$I=\frac{0.3}{3}[(\ln 4+\ln 5.2)+4\left(\ln 4.3+\ln 4.9\right)+2\left(\ln 4.6\right)]$

∴ I = 1.8278 ≈ 1.83