Question

What should be the elevation of outer track of the train to move in a circular path of radius R, width of the track is w (< < R) and speed of the train is v ? (Neglect friction)

Options :

  1. v2w / Rg

  2. v2w / 2Rg

  3. gwv2 / R

  4. R / gwv2

Show Answer

Answer :

v2w / Rg

Solution :


N s i n θ = m v 2 R Ncosθ = mg t a n θ = v 2 R g = h w h = v 2 w R g

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