Question
When a 4 kg mass is hung vertically on a light spring that obeys Hooke’s law, the spring stretches by 2 cms. The work required to be done by an external agent in the stretching this spring by 5 cms will be (g = 9.8 m/s²)
Options :
4.900 J
2.450 J
0.495 J
0.245 J
Answer :
2.450 J
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