Question

Z = 20x1 + 202, subject to x1 ≥ 0, x2 ≥ 0, x1 + 2x2 ≥ 8, 3x1 + 2x2 ≥ 15, 5x1 + 2x2 ≥ 20. The minimum value of Z occurs at

Options :

  1. (8, 0)

  2. (5/2, 15/4)

  3. (7/2, 9/4)

  4. (0, 10)

Show Answer

Answer :

(7/2, 9/4)

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