JEE (Mains) - 29 Jan 2024 (Shift - 1)

# Q1 of 54

A body of man 100 kg travelled 10 m before coming to rest. If μ = 0.4, work done against friction is (motion is happening on horizontal surface, take g = 10 m/s2)

Options :
A.

4500 J

B.

5000 J

C.

4200 J

D.

4000 J

Show Answer
Answer :

4000 J

Solution :

V2/ 2a = S  (a = µg)

V2 = 2 × µgs

V2 = 2 x (.4) x 10 x 10

V2 = 80

Wf = Δk

= -1/2 × 100 × 80

Wf = -4000

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